FashionIncomingSwarovski Film Premiere: Anna Vs AnnaDirector/photographer Barnaby Roper's latest work showcases the collaboration through a unique film feature, shown here exclusively on Dazed DigitalShareLink copied ✔️January 23, 2012FashionIncomingTextDazed DigitalSwarovski Film Premiere: Anna Vs Anna ‘Anna vs. Anna’, is the new avant garde film created exclusively for Swarovski - starring model Anna Jagodzinska adorned in a selection of exquisite fashion pieces, selected by stylist Keegan Singh, from the archives of Rodarte. The haunting film by director and photographer Barnaby Roper, showcases each of the looks, each shimmering with Swarovski Elements crystals as part of their ongoing collaboration. Inspired by the supernatural, Roper's film is an attempt to portray the two sides of 'Anna’s character, transporting the viewer magically from the shadows to brilliant light. The unique experience allows you to manipulate and interact with the imagery in a full 360°, through its unique technology to push the boundaries of film in fashion. "This film is a journey from darkness to light. It starts off in a very dark place, and then we slowly come out of it into the light", director Barnaby Roper said of the film. Expand your creative community and connect with 15,000 creatives from around the world.READ MOREMeet Bhavitha Mandava, the history-making, hobbymaxxing Chanel modelInside Michaela Stark’s provocative, Leigh Bowery-inspired 2026 calendarThe 2025 Dazed 100 USA list is hereBlink and you’ll miss ‘em: Dario Vitale’s greatest Versace hitsTimothée and Kylie really need you to know that they’re still togetherMartine Rose: ‘Limits are good, but I like breaking the rules’Kısmet by MilkaKate Moss takes over London for Kısmet by MilkaFrom Lana to Gaga: August Barron curate their ultimate music video nightInside the world of August Barron, fashion’s disruptive design duoIn pictures: Shalom Harlow’s most iconic catwalk momentsSilver Arrows: Fusing fashion with film noirSo you want to get your hands on Leigh Bowery’s merkin?